Problems on Train Questions with Solution

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Problems on Train is an important topic from the government exam point of view. The train-related questions are frequently asked in many competitive exams such as - Railway, SSC, Bank, or State Government exams. The weightage of questions asked from this topic is mostly between 1-3 marks.

 If you want to get command over this chapter then it is very important to understand its basic concept first. If you understand its basic concept then you can easily solve any type of question whether it is easy or difficult.

In this article, we will cover all types of questions related to trains. And all types of trains question with solution is given here. 

Table of Content Basic concept Simple formula based questions Conversion based questions Stable object with no length Stable object with length Running object with no length Running object in the same direction of train Running object in the opposite direction of train Running object with length Running object in the same direction of train Running object in the opposite direction of train Mixed questions

First, we will see the formula which we use to solve the train’s question. 

Basic Concept

Speed = Distance/Time If the distance is in kilometers and the time is in the hour so speed = km/hr If the distance is in meters and the time is in a second so the speed = m/s To convert the speed in km/hr to m/s, we multiply it with 5/18 - speed*km/hr = (speed*5/18)m/s To convert the speed in m/s to km/hr, we multiply it with 18/5 - speed*m/s = (speed*18/5)km/hr When a train crosses a stationary object like a man, pole, or tree. In this case, the distance traveled is the length of the train.  When a train crosses a stationary object like a platform/ bridge (which has length). In this case, the distance traveled is the length of the train and the length of the object. If the length of the platform/bridge is a and the length of the train is b so the total distance = a+b If two trains are moving in the same direction at x m/s and y m/s so the relative speed = (x - y) m/s If two trains are moving in the opposite direction at x m/s and y m/s so the relative speed = (x+y) m/s If two trains of length a meters and b meters are moving in the same direction at x m/s and y m/s, then the time is taken by the faster train to cross the slower train = a+b / x-y If two trains of length a meters and b meters are moving in opposite directions at x m/s and y m/s then the time taken by the trains to cross each other = a+b / x+y Two trains start from two points A and B at the same time and move towards each other. These trains take x and y seconds to reach points A and B respectively, the relation between them is - Speed of A/Speed of B = √y/√x

Now we will see the different types of questions that come from this topic. 

Problems on Trains Question with explanation

1. Simple Formula Based Questions

In simple formula-based questions, only by applying the formula, we get the answer. The formula is - Speed = (Distance/Time). If distance and time or speed and distance or speed and time are given so we can easily find the third one. The example of formula based simple question is given below - 

2. Conversion Based questions

In the conversion-based question, if the speed is given in km/hr and we have to find the speed into m/s, so we multiply the speed which is given in km/hr with 5/18.

If the speed is given in m/s and we have to find the speed into km/hr so we multiply the speed which is given in m/s with 18/5. Don't get confused the example of conversion-based questions is given below - 

3. Stable Object With No Length

In this type of question, it is given that a train crosses a stable object like a man, pole, lamp post, or tree and you are required to find either the speed of train or length of train or time taken by train to cross the object. 

When a train crosses these stationary objects, in this case, the total distance covered is the length of the train Because after meeting the object the distance traveled by the train in crossing the object is equal to the length of the train. The example is given below - 

4. Stable Object With Length

When a train crosses a stationary object like a platform/ bridge/tunnel (which has length). In this case, the distance traveled is the length of the train and the length of the object. If the length of the platform/bridge/tunnel is a and the length of the train is b so the total distance covered = a+b. The example is given below - 

5. Running Object With No Length

There are two conditions - If a man is running in the same direction of the train or if the man running in the opposite direction of the train.

5.1. Running object in the same direction of train

If a man is running in the direction of the train and the speed of the train is x m/s and the speed of man is y m/s, so the relative speed will be (x-y) m/s. And the total distance covered will be the length of the train. The example is given below -

5.2. Running object in the opposite direction of train

If a man is running in the opposite direction of the train and the speed of the train is x m/s and the speed of man is y m/s, so the relative speed will be (x+y) m/s. And the total distance covered will be the length of the train. The example is given below -

6. Running Object With Length

There are two conditions - If the trains are running in the same direction of each other or if the trains are running in the opposite direction of each other.

6.1. Running object in the same direction 

If two trains are moving in the parallel direction at the speed of xm/s and ym/s so the relative speed = (x-y) m/s

If two trains of length a meters and b meters are moving in the same direction at the speed of x m/s and y m/s, then the time is taken by the faster train to cross the slower train = a+b / x-y. The example is given below - 

6.2. Running object in the opposite direction 

If two trains are moving in the opposite direction at the speed of x m/s and y m/s so the relative speed = (x+y) m/s 

If two trains of length a meter and b meters are moving in opposite directions at the speed of x m/s and y m/s then the time taken by the trains to cross each other = a+b / x+y. The example is given below - 

Mixed questions

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