If 1/N = ( v6 + v5)/( v6 - v5), then what is the value of N?

यदि 1/N = ( √6 + √5) / ( √6 - √5), तो N का मान क्या है?

A.6 - v30(6 - √30)

B.6 + v30(6 + √30)

C.11 - 2v30(11 - 2√30)

D.11 + 2v5(11 + 2√5)

Answer

C. 1/N = ( √6 + √5) / ( √6 - √5) N = ( √6 - √5) / ( √6 + √5) N = [( √6 - √5) / ( √6 + √5)] * [( √6 - √5) / ( √6 - √5)] N = ( √6 - √5)^2/6-5 N = 6+5-2 √6 √5 N = 11-2 √6 √5 N = 11-2 √30 So the correct answer is option C.

C. 1/N = ( √6 + √5) / ( √6 - √5) N = ( √6 - √5) / ( √6 + √5) N = [( √6 - √5) / ( √6 + √5)] * [( √6 - √5) / ( √6 - √5)] N = ( √6 - √5)^2/6-5 N = 6+5-2 √6 √5 N = 11-2 √6 √5 N = 11-2 √30 इसलिए सही उत्तर विकल्प C है।