Question
If a + b + c = 27, then what is the value of (a – 7)^3 + (b – 9)^3 + (c – 11)^3 – 3(a – 7)(b – 9)(c – 11)?
यदि a + b + c = 27, तो (a - 7)^3 + (b - 9)^3 + (c - 11)^3 - 3 [(a - 7) (b - 9) (c -11)] का मान क्या है?
Answer A.
A.If x+y+z=0
x^3+y^3+z^3=3xyz
a + b + c = 27
= (a - 7) + (b - 9) +(c - 11) = 0.
=(a−7)^3+(b−9)^3+(c−11)^3=3(a−7)(b−9)(c−11)
=(a−7)^3+(b−9)^3+(c−11)^3−3(a−7)(b−9)(c−11)
=0
So the correct answer is option A.
A.यदि x+y+z=0
x^3+y^3+z^3=3xyz
a + b + c = 27
= (a - 7) + (b - 9) +(c - 11) = 0.
=(a−7)^3+(b−9)^3+(c−11)^3=3(a−7)(b−9)(c−11)
=(a−7)^3+(b−9)^3+(c−11)^3−3(a−7)(b−9)(c−11)
=0
इसलिए सही उत्तर विकल्प A है।
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