If x4 + 1/x4=34 then what is the value of x3 – (1/x3)?

यदि x⁴ + 1/x⁴=34, तो (x³ - 1/x³) का मान क्या है?

D.x⁴ + 1/x⁴=34 add 2 x² × 1/x² both side- x⁴ + 1/x⁴ + 2x² × 1/x² = 34 + 2x² × 1/x² (x² + 1/x²)² = 34 + 2 =(x² + 1/x²)² = 36 = (x² + 1/x²) = √36 = x² + 1/x² = 6 Again, subtract 2x × 1/x from both sides, x² + 1/x² - 2x × 1/x = 6 - 2x × 1/x =(x - 1/x)² = 6 - 2 =(x - 1/x)² = 4 = x - 1/x = √4 =x - 1/x = 2 (x - 1/x)^3=x³ - 1/x³ - 3 x * 1/x (x - 1/x) (2)^3=x³ - 1/x³ - 3 *(2) 8+6=x³ - 1/x³ x³ - 1/x³ =14 So the correct answer is option D.

D.x⁴ + 1/x⁴=34 2 x² × 1/x² को दोनों तरफ जोड़ने पर - x⁴ + 1/x⁴ + 2x² × 1/x² = 34 + 2x² × 1/x² (x² + 1/x²)² = 34 + 2 =(x² + 1/x²)² = 36 = (x² + 1/x²) = √36 = x² + 1/x² = 6 दोबारा 2x × 1/x को दोनों ओर घटाने पर x² + 1/x² - 2x × 1/x = 6 - 2x × 1/x =(x - 1/x)² = 6 - 2 =(x - 1/x)² = 4 = x - 1/x = √4 =x - 1/x = 2 (x - 1/x)^3=x³ - 1/x³ - 3 x * 1/x (x - 1/x) (2)^3=x³ - 1/x³ - 3 *(2) 8+6=x³ - 1/x³ x³ - 1/x³ =14 इसलिए सही उत्तर विकल्प D है।

(4^61 + 4^62 + 4^63 + 4^64) is divisible by:

(4^61 + 4^62 + 4^63 + 4^64) विभाज्य है :

How many diagonals are there in octagon?

अष्टभुज में कितने विकर्ण होते हैं?

In an examination, 34% of the students failed in Mathematics and 42% failed in English. If 20% of the students failed in both the subjects, then the percentage of students who passed in both the subjects was :

एक परीक्षा में, 34% छात्र गणित में और 42% अंग्रेजी में असफल रहे। यदि दोनों विषयों में 20% छात्र फेल हो गए, तो दोनों विषयों में उत्तीर्ण छात्रों का प्रतिशत था:

A sum of money doubles itself at compound interest in 10 years. In how many years will it be eight times?

10 साल में चक्रवृद्धि ब्याज पर एक धन दोगुना हो जाता है। कितने वर्षों में यह आठ गुना होगा?